Solve problem "Leap year" online - Learn Python 3 - Snakify

Problem «Leap year» (Easy)


Statement

Given the year number. You need to check if this year is a leap year. If it is, print LEAP, otherwise print COMMON.

The rules in Gregorian calendar are as follows:

  • a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
  • a year is always a leap year if its number is exactly divisible by 400

Warning. The words LEAP and COMMON should be printed all caps.


In all the problems input the data using input() and print the result using print().



Saved solutions

Tests

Input Correct answer Result
2012
LEAP
2011
COMMON
1492
LEAP
1861
COMMON
1600
LEAP
1700
COMMON
1800
COMMON
1900
COMMON
2000
LEAP