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- 2. Целочисленные и плавающие числа
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- 4. Для контура с диапазоном
- 5. Струны
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- 9. Двумерные списки (массивы)
- 10. наборы
- 11. Словари
- 12. JavaScript
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- 14. Responsive Design with Bootstrap
- 15. jQuery
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Leap year
Statement
Given the year number. You need to check if this year is a leap year. If it is, printLEAP
, otherwise print COMMON
. The rules in Gregorian calendar are as follows:
- a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
- a year is always a leap year if its number is exactly divisible by 400
Warning. The words LEAP
and COMMON
should be printed all caps.
In all the problems input the data using input()
and print the result using print()
.
12# Read an integer:# a = int(input())XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
Input:
12012XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
Output:
1XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
Saved solutions
Tests
Input | Correct answer | |
---|---|---|
2012 | LEAP | |
2011 | COMMON | |
1492 | LEAP | |
1861 | COMMON | |
1600 | LEAP | |
1700 | COMMON | |
1800 | COMMON | |
1900 | COMMON | |
2000 | LEAP |