Solve problem "Leap year" online - Learn Python 3 - Snakify

Leap year


Statement

Given the year number. You need to check if this year is a leap year. If it is, print LEAP, otherwise print COMMON.

The rules in Gregorian calendar are as follows:

  • a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
  • a year is always a leap year if its number is exactly divisible by 400

Warning. The words LEAP and COMMON should be printed all caps.


In all the problems input the data using input() and print the result using print().

# Read an integer:
# a = int(input())
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
Input:
2012
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
Output:
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

Saved solutions

Tests

InputCorrect answer
2012
LEAP
2011
COMMON
1492
LEAP
1861
COMMON
1600
LEAP
1700
COMMON
1800
COMMON
1900
COMMON
2000
LEAP