- 1. Giriş, baskı ve sayılar
- 2. Tam sayı ve kayan sayıları
- 3. Koşullar: eğer-o-else
- 4. Aralıklı döngü için
- 5. Teller
- 6. Döngü sırasında
- 7. Listeler
- 8. İşlevler ve özyineleme
- 9. İki boyutlu listeler (diziler)
- 10. Setler
- 11. Sözlükler
- 12. JavaScript
- 13. HTML5 and CSS
- 14. Responsive Design with Bootstrap
- 15. jQuery

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# Leap year

## Statement

Given the year number. You need to check if this year is a leap year. If it is, print`LEAP`

, otherwise print `COMMON`

. The rules in Gregorian calendar are as follows:

- a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
- a year is always a leap year if its number is exactly divisible by 400

**Warning.** The words `LEAP`

and `COMMON`

should be printed all caps.

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In all the problems input the data using `input()`

and print the result using `print()`

.