Solve problem "Leap year" online - Learn Python 3 - Snakify

Leap year


Statement

Given the year number. You need to check if this year is a leap year. If it is, print LEAP, otherwise print COMMON.

The rules in Gregorian calendar are as follows:

  • a year is a leap year if its number is exactly divisible by 4 and is not exactly divisible by 100
  • a year is always a leap year if its number is exactly divisible by 400

Warning. The words LEAP and COMMON should be printed all caps.

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In all the problems input the data using input() and print the result using print().

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